The bath was filled with water weighing 120 kg at a temperature of 20 degrees and water weighing 240 kg
| September 17, 2021 | education
The bath was filled with water weighing 120 kg at a temperature of 20 degrees and water weighing 240 kg at a temperature of 90 degrees. Find the temperature of the mixture
Initial data: m1 (mass of cool water) = 120 kg; t1 (cool water temperature) = 20 ºС; m2 (hot water mass) = 240 kg; t2 (hot water temperature) = 90 ºС.
The steady-state temperature of the mixture can be determined from the following equality:
C * m1 * (t3 – t1) = C * m2 * (t2 – t3).
m1 * (t3 – t1) = m2 * (t2 – t3).
120 * (t3 – 20) = 240 * (90 – t3).
120t3 – 2400 = 21600 – 240t3.
360t3 = 24000.
t3 = 24000/360 = 66.7 ºС.
Answer: The temperature of the water mixture in the bathroom will be 66.7 ºС.
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