The battery, the EMF of which is 16 V, is closed on a 6 Ohm resistor, the current in the circuit is 2 A.

| April 25, 2021 | education

The battery, the EMF of which is 16 V, is closed on a 6 Ohm resistor, the current in the circuit is 2 A. Determine the internal resistance of the battery.

EMF = 16 V.

R = 6 ohms.

I = 2 A.

r -?

According to Ohm’s law for a closed loop, the current in the circuit I is directly proportional to the electromotive force of the current source EMF and is inversely proportional to the sum of the external resistance R and the internal resistance of the current source r: I = EMF / (R + r).

Let us express the sum of resistances: R + r = EMF / I.

The internal resistance of the current source will be determined by the formula: r = EMF / I – R.

Let’s substitute the data from the problem statement: r = 16 V / 2 A – 6 Ohm = 2 Ohm.

Answer: the current source has a resistance r = 2 ohms.



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