The bike moves evenly around a circle with a radius of 200m and makes one revolution in 2 minutes.

The bike moves evenly around a circle with a radius of 200m and makes one revolution in 2 minutes. Determine the path and module of movement of the bike in 1 min; 2 min.

R = 200 m.

T = 2 min = 120 s.

t1 = 1 min = 60 s.

t2 = 2 min = 120 s.

S1 -?

L1 -?

S2 -?

L2 -?

The traversed path L is the length of the trajectory that the body passes when moving. The movement of the body S is a vector that connects the initial and final position of the body.

The time of one complete revolution t2 = T is called the rotation period. During this time, the cyclist returns to the starting position, his starting and ending positions coincide. The traversed path L2 will be the length of a circle with a radius R, the movement of the body S2 = 0.

L2 = 2 * P * R.

L2 = 2 * 3.14 * 200 m = 1256 m.

During the movement t1 = 60 s, the cyclist travels half the length of the circle L1 = 2 * P * R / 2, the movement of S1 will be the diameter of the circle S1 = 2 * R.

L1 = 2 * 3.14 * 200 m / 2 = 628 m.

S1 = 2 * 200 m = 400 m.

Answer: L1 = 628 m, S1 = 400 m, S2 = 0, L2 = 1256 m.