The binding energy of the nucleus of a lithium atom is 29.88 MeV. Find in a.u. the mass defect of this nucleus.
| January 12, 2021 | education
To solve this problem, you need to use the following formula:
E sv = Δm * 931 MeV;
Thus, we need to transform the formula:
Δm = Ew / 931 MeV;
Substitute the values into the transformed formula:
Δm = 29.88 MeV / 931 MeV;
We get:
Δm = 0.0321 amu
Answer: Δm = 0.0321 amu.
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