The bisector AD is drawn in an equilateral triangle ABC. The distance from point D to line AC is 6 cm
| February 17, 2021 | education
The bisector AD is drawn in an equilateral triangle ABC. The distance from point D to line AC is 6 cm. Find the distance from vertex A to line BC.
Since triangle ABC, by condition, is equilateral, all of its angles are 60.
AD is a bisector, then the angle DAC = 60/2 = 30.
The ADН triangle is rectangular, since the DН is perpendicular to the AC, then the leg of the DН lies against the angle of 60, then the hypotenuse AD = 2 * DН = 2 * 6 = 12 cm.
The bisector of the blood pressure of an equilateral triangle is also its height, then from point A to the side BC 12 cm.
Answer: From point A to BC 12 cm.
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