The bisector AD is drawn in an isosceles triangle ABC with base AC. Find ∠ADC if ∠C = 50 °.
| March 13, 2021 | education
The angles at the base of an isosceles triangle are equal, so the angle A = angle C = 50 °.
The bisector AD divides the angle A in half, then the angle CAD = angle DAB = 50 °: 2 = 25 °.
Consider triangle ADC. Knowing the magnitude of the two angles, we find the third angle ADC.
Angle ADC = 180 ° – (50 ° – 25 °) = 105 °.
Answer: The ADC angle is 105 °.
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