The bisector AL is drawn in the triangle ABC, the angle ALC is 102, the angle ABC is 96. Find the angle ACB.

For triangle ABL: ∟ALC – external and equal to the sum of two internal angles, not adjacent to it.
∟АLC = ∟АВL + ∟ВАL
∟ВАL = 102˚- 96˚ = 6˚.
AL is a bisector, therefore the whole ∟A = 2 * 6˚ = 12˚
Consider a triangle ABC: ∟A = 12˚, ∟B = 96˚, and the sum of the angles of the triangle is 180˚
∟С = 180˚- (12˚ + 96˚) = 72˚.



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