The bisector am of the parallelogram abcd divides the side bc into segments bm = 5 cm
| September 15, 2021 | education
The bisector am of the parallelogram abcd divides the side bc into segments bm = 5 cm, mc = 8 cm. Find the perimeter of the parallelogram.
Since AM is the bisector of the angle BAD, it forms an isosceles triangle at the lateral side AB, then BM = AB = 5 cm.
The length of the longer side of the parallelogram BC = BM + CM = 5 + 8 = 13 cm.
By the property of a parallelogram, the lengths of its opposite sides are equal, then AB = CD = 5 cm, AD = BC = 13 cm.
The perimeter of the parallelogram ABCD is:
Ravsd = 2 * (AB + BC) = 2 * (5 + 13) = 36 cm.
Answer: The perimeter of the parallelogram is 36 cm.
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