The bisector AP is drawn in an isosceles triangle ABC with base AC. Find the APB angle if the ACB angle is 74 degrees.

Since the triangle ABC is isosceles, the angle ABC = BCA = 74.

Then the angle ABC = (180 – 74 – 74) = 32.

AP is the bisector of angle A, then the angle VAR = 74/2 = 37.

In the ABP triangle, the ABP angle = (180 – 32 – 37) = 111.

Answer: The value of the angle ABP is 111.



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