The bisector BD divides the side AC of triangle ABC into segments AD and CD

The bisector BD divides the side AC of triangle ABC into segments AD and CD, equal to 6 cm and 9 cm, respectively, AB = 8 cm. What is the perimeter of triangle ABC?

We will use the property of the bisector of a triangle, according to which, the bisector divides the opposite side of the triangle into segments proportional to the adjacent sides.

Then CD / CB = AD / AB.

CB = CD * AB / AD = 9 * 8/6 = 12 cm.

Determine the length of the AC side. AC = AD + CD = 6 + 9 = 15 cm.

Then the perimeter of the triangle is: Ravs = (AB + BC + AC) = 8 + 12 + 15 = 35 cm.

Answer: The perimeter of triangle ABC is 35 cm.



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