The bisector BK is drawn in parallelogram ABCD. AD = 7cm, AB = 8cm, BK = 9cm. Find the perimeter of the ADKB.

univerkov | June 22, 2021 | education

In order to solve this problem, draw a picture and look at the picture to look for a solution. The solution will follow: Angle KBA = angle CBA, because BK is a bisector.
Angle КBА = angle СКB, as a cross lying angle with BC parallel to AD. It follows from this that the triangle BCK is isosceles. BC = CK = 7 cm.
КD = 8 – 7 = 1 cm.
Perimeter ADKB = 7 + 1 + 9 + 8 = 25 cm.
Therefore, our answer is 25 cm.

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