The bisector CE is drawn in triangle ABC. Find the angle BCE if ∠BAC = 46 ° and ∠ABC = 78 °.

univerkov | November 30, 2020 | education

1.BCA angle = 180 ° – (BAC angle + ABC angle) = 180 ° – (46 ° + 78 °) = 180 ° -124 ° = 56 °
2. Since the bisector CE divides the angle of the BCA in half, then the angle ВСЕ = 56: 2 = 28 °
Answer: angle ВСЕ = 28 °

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