The bisector of a parallelogram angle intersects its side, forming an angle of 48 degrees with it. Find the angles of a parallelogram.

Let ABCD be a parallelogram, point P – the point of intersection of the bisector AP with the side of the parallelogram BC.
Angle DAP = BPA, as these are criss-cross corners. And since BAP = BPA, it follows that the BAP triangle is isosceles.
Angle A is equal to the sum of the angles ВAR and PAD.
Angle A = 48 + 48 = 96 = angle C (opposite angles in the parallelogram are equal)
Angle B is 180 – (ВAR angle + BPA angle)
Angle B = 180 – (48 + 48) = 84 = Angle D
Answer: angle A = angle C = 96, angle B = angle D = 84