The bisector of a parallelogram angle intersects the opposite side at an angle of 55 degrees.
| April 18, 2021 | education
The bisector of a parallelogram angle intersects the opposite side at an angle of 55 degrees. Find the degree measure of the parallelogram angles.
Let ABCD be a parallelogram, and BE the bisector of angle BAD. Angle EAB = angle EAD = angle BEA = 55 (degrees) (<EAB = <EAD as equal angles divided by the bisector AE, and <EAD = <AEB, as internally criss-crossing angles with parallel lines AD and BC. Thus.
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