# The bisector of an acute angle of a parallelogram divides its side into segments 7 and 5

October 5, 2021 | education

| **The bisector of an acute angle of a parallelogram divides its side into segments 7 and 5, counting from the apex of the obtuse angle. The perimeter of the parallelogram is?**

The bisector AM of the angle BAC cuts off the isosceles triangle ABM from the lateral side AB, then AB = AM = 7 cm.

Side length BC = BM + CM = 7 + 5 = 12 cm.

In a parallelogram, the lengths of the opposite sides are equal, then SD = AB = 7 cm, BC = AD = 12 cm.

The perimeter of the parallelogram is: Ravsd = 2 * (AB + AD) = 2 * (7 + 12) = 2 * 19 = 38 cm.

Answer: The perimeter of the parallelogram is 38 cm.

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