The bisector of an acute angle of a parallelogram divides its side into segments 7 and 5, counting from the apex of the obtuse angle. The perimeter of the parallelogram is?
The bisector AM of the angle BAC cuts off the isosceles triangle ABM from the lateral side AB, then AB = AM = 7 cm.
Side length BC = BM + CM = 7 + 5 = 12 cm.
In a parallelogram, the lengths of the opposite sides are equal, then SD = AB = 7 cm, BC = AD = 12 cm.
The perimeter of the parallelogram is: Ravsd = 2 * (AB + AD) = 2 * (7 + 12) = 2 * 19 = 38 cm.
Answer: The perimeter of the parallelogram is 38 cm.
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