The bisector of an equilateral triangle is 11 root 3, find its side.

Let the side of an equilateral triangle ABC be equal to a. Triangle angles <A = <B = <C = 60 °. The bisector of an equilateral triangle AM coincides with the height and median. Since AM is the height, its value is found by the formula:

AM = AB * sin (60 °) = a * (√ 3/2) = 11 * √ 3.

From here we define the side of the triangle:

AB = BC = AC = a = (11 * √ 3) / (√ 3) / 2 = 22.



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