The bisector of angle A is drawn in parallelogram ABCD, which intersects side BC at point K.
| June 20, 2021 | education
The bisector of angle A is drawn in parallelogram ABCD, which intersects side BC at point K. Prove that ABK is isosceles.
Since AK is the bisector of the angle BAD, the angle BAK = DAK.
Angle ВКА = DАК as criss-crossing angles at the intersection of parallel straight lines АD and ВС secant АD.
Then the angle ВAK = ВKA, and if in a triangle the angles at the base are equal, then such a triangle is isosceles, which was required to prove.
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