The bisector of angle A of an isosceles triangle ABC intersects the circumscribed circle at point D
May 27, 2021 | education
| The bisector of angle A of an isosceles triangle ABC intersects the circumscribed circle at point D. Find the angles A B, C if the angle BDC = 70 degrees.
The angle BDE rests on the same arc BC, on which the angle <A rests (at the base of an isosceles triangle). Therefore <A = <BDC = 70 °.
The angles at the base of an isosceles triangle are:
<C = <A = 70 °.
<B = 180 ° – <C – <A = 180 ° – 70 ° – 70 ° = 40 °.
Answer: <A = 70 °, <B = 40 °, <C = 70 °.
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