The bisector of angle A of parallelogram ABCD intersects line BC at point E
| September 24, 2021 | education
The bisector of angle A of parallelogram ABCD intersects line BC at point E., angle AEC is equal to 154 degrees. find the large angle of the parallelogram.
Let the angle BAD = X0, then the angle ABC = (180 – X) 0, the angle BAM = X / 2.
The angle AEC is the outer angle of the triangle ABE, then the angle AEC = (ABE + BAE) = (180 – X + X / 2) = 154.
0.5 * X = 26.
X = BAD = 26 / 0.5 = 52, then the angle ABC = (180 – 52) = 128.
Answer: The larger angle of the parallelogram is 128.
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