The bisector of angle A of the parallelogram ABCD intersects the side BC at point K. Find KC if AB = 5 cm and AD = 7 cm.

Since ABCD is a parallelogram, its opposite sides are equal and parallel.

Then the angle DAK = BKA as the cross-lying angles at the intersection of parallel straight lines AD and BC secant AK.

Then in the triangle ABK the angle BAK = BKA, which means that the triangle ABK is isosceles, BK = AB = 5 cm.

BC = AD = 7 cm.

Then KC = BC – BK = 7 – 5 = 2 cm.

Answer: The length of the segment KC is 2 cm.



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