The bisector of angles A and B of triangle ABC intersect at point L and angle ALB is 130 degrees.

The bisector of angles A and B of triangle ABC intersect at point L and angle ALB is 130 degrees. Find the angles of triangle ABC, given that the angle CBL is 34 degrees.

Since ВL is the bisector of the angle ABC, and the angle CBL = ABL = 340, then the angle ABC = 34 * 2 = 68.

The angle ALB, by condition, is 130, then the angle BAL = 180 – 130 – 34 = 16.

Then the angle BAC = 2 * 16 = 32.

Find the angle of the BCA.

BCA = 180 – 32 – 68 = 80.

Answer: The angles of the triangle ABC are equal:

ABC = 68, BAC = 32, BAC = 80.



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