The bisector of one of the corners of the parallelogram divides its side into segments
| August 23, 2021 | education
The bisector of one of the corners of the parallelogram divides its side into segments 12 and 7 cm long. find the perimeter of the parallelogram.
The bisector BM of the angle ABC forms an isosceles triangle ABM on the lateral side AB, then AB = AM = 12 cm.
Side length AD = AM + DM = 12 + 7 = 19 cm.
Since the opposite sides of the parallelogram are equal, then CD = AB = 12 cm, BC = AD = 19 cm.
The perimeter of the parallelogram is: Ravsd = 2 * (AB + AD) = 2 * (12 + 19) = 2 * 31 = 62 cm.
Answer: The perimeter of the parallelogram is 62 cm.
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