The bisector of the angles A and B of the triangle ABC intersect at point M. Find the angle AMB

The bisector of the angles A and B of the triangle ABC intersect at point M. Find the angle AMB, if the angle A = 58 °, the angle B = 96 °.

The bisector divides the angle in half. That’s why:
MAB angle = CAB angle / 2 = 58/2 = 29 degrees;
MBA angle = CBA angle / 2 = 96/2 = 48 degrees.
Since the sum of the angles of any triangle is 180 degrees, then
AMB angle + MAB angle + MBA angle = 180
Angle AMB = 180 – 29 – 48 = 103 degrees
Answer: 103 degrees.



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