The bisector of the outer angle at the apex of an isosceles triangle forms

The bisector of the outer angle at the apex of an isosceles triangle forms an angle of = 70 degrees with the lateral side. find the corners of the triangle.

Find the outer angle at the apex of an isosceles triangle:
2 * 70 ° = 140 °
The inside angle at the apex of the triangle is:
180 ° – 140 ° = 40 °.
The degree measure of the external angle at the apex is known; it is a wound by the degree measure of two internal angles that are not adjacent to it.
It turns out that the two angles at the base are equal to 140 °. The angles at the base are equal, the degree measure of each:
140 ° / 2 = 70 °.
Answer: the angles of the triangle are 70 °, 70 °, 40 °.