The bisector of the parallelogram ABCD divides its side BC into segments BK = 19cm and KC = 10cm. Find its perimeter

The bisector of a parallelogram separates an isosceles triangle from it => ABK – isosceles => AB = BK = 19 cm. AB = CD = 19 cm. (By the parallelogram property) BC = BK + KC = 19 + 10 = 29 cm. BC = AD = 29 cm. (By the parallelogram property) P = AB + CD + BC + AD = 78 cm.
Answer: P = 78 cm.



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