The bisectors of angles A and B of triangle ABC intersect at point M Find the angle AMB If angle A = 58 ‘, angle B = 96’.

Since BH and AK are the bisectors of the angles ABC and BAC, respectively, they divide these angles in half.

Then the angle ABK = SAK = BAK / 2 = 58/2 = 29, the angle ABN s СBN = ABC / 2 = 96/2 = 48.

In triangle ABM, the sum of the internal angles of which is 180, we determine the value of the angle AMB.

Angle AMB = (180 – BAM – ABM) = (180 – 29 – 48) = 103.

Answer: The value of the angle AMB is equal to 103.



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