The bisectors of the angles M and K of the isosceles triangle MNK meet at point O.

The bisectors of the angles M and K of the isosceles triangle MNK meet at point O. Find the angle MOK if the angle is P = 48.

Since the MRK triangle is isosceles, the angle PMK = PCM = (180 – MRK) / 2 = (180 – 40) / 2 = 70.

Segments MA and KB of the bisector, then the angle ОМА = РМК / 2 = 70/2 = 450, angle PCM = 70/2 = 45.

Then the angle MOC = (180 – 45 – 45) = 90.

Answer: The IOC angle is 90.



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