The bisectors of triangle ABC meet at point S. Find the angle SCA if the angle ASB is 134 °.

Consider the triangle ABS. The sum of the ABS and BAS angles is 180 ° – 134 ° = 46 °. Since the sides AS and BS turn out to be the bisectors of the angles A and B, then, i.e., these angles in total are equal to 92 °. Then the angle C will be 180 ° – 92 ° = 88 °. Since CS is the bisector of C, the SCA is half of C. The SCA is therefore 44 °.



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