The bissictrix EF is drawn in a rectangular DCE with a right angle С. FC = 13cm. find the distance from point F to line DE

Consider triangles ECF and EHF. Both triangles are rectangular, since the angle C = 90, and FH is perpendicular to DE.

The hypotenuse EF of the triangles is common, the angle CEF = HEF since EF is the bisector of the SED angle, then the right-angled triangles ECF and EHF are equal in hypotenuse and acute angle, and therefore FH = FC = 13 cm.

Answer: The length of the FH segment is 13 cm.



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