The block evenly lifts a weight of 200 kg to a height of 3 m for 5 seconds. Determine the power of the block.

The power of the block can be calculated by the formula:

P = A / t, where A is the work done by the block (A = F * S, where F is the applied force, F = Ft = m * g (m is the mass of the load being lifted (m = 200 kg)), g is the acceleration of the free fall (we take g = 10 m / s2)); S – displacement, height of lifting the load (S = h = 3 m)), t – time of lifting the load (t = 5 s).

Let’s calculate the power of the block:

P = A / t = m * g * h / t = 200 * 10 * 3/5 = 1200 W = 1.2 kW.

Answer: The power of the unit is 1.2 kW.