The boat sails along the river at a speed of 24 km / h. The current speed is 2 km / h.
The boat sails along the river at a speed of 24 km / h. The current speed is 2 km / h. How fast will the boat sail on the way back?
Speed of the boat downstream (V downstream) = 24 km / h;
Current speed (Vflow) = 2 km / h;
Speed of the boat against the current (Vpr. Flow) -? km / h.
The speed of the boat downstream is the sum of the boat’s own speed (or its speed in still water) and the speed of the river.
That. Vin flow = Vsob. + Vcur.
Therefore, Vsobst. = Vin flow. – V leak. = 24 – 2 = 22 (km / h).
The speed of the boat against the current is the difference between the boat’s own speed (or its speed in still water) and the speed of the current of the river, which prevents the boat from moving.
That. Vpr. tech. = Vsob. – V leak. = 22 – 2 = 20 (km / h).
Answer: the boat will sail at a speed of 20 km / h on the way back.