The boat’s own speed is 15 as much as 2/3 km / h and the current speed is 15 km / h.
The boat’s own speed is 15 as much as 2/3 km / h and the current speed is 15 km / h. How many times the speed of a boat sailing with the stream is greater than the speed of a boat sailing against the stream of the river.
v к = 15 2/3 km / h – speed of the boat in still water
v t = 1.5 km / h – the speed of the river.
Let’s find the speed at which the boat is moving with the current:
v1 = v k + v t = 15 2/3 + 1.5 = 47/3 + 15/10 = (470 + 45) / 30 = 515/30 km / h.
Let’s determine the speed of the boat against the river flow:
v2 = v k – v t = 15 2/3 – 1.5 = 47/3 – 15/10 = (470 – 45) / 30 = 425/30 km / h.
Let’s calculate how many times faster the boat moves with the current:
v1 / v2 = 515/30: 425/30 = 515/425 = 103/85 = 1.21.
Answer: the boat goes downstream 1.21 times faster than against the current.