The body begins to move from a state of rest and moves for 10 s uniformly accelerated with an acceleration

| February 1, 2021 | education

The body begins to move from a state of rest and moves for 10 seconds uniformly accelerated with an acceleration of 4m / s2, then the movement of the body becomes equally slowed down with an acceleration of 2m / s / sq and the body stops to find the path traveled by the body.

To find the path traversed by a given body with equal motion, use the formula: S = S1 + S2 = (a1 * t1 ^ 2/2) + (a1 * t1 * t2 – a2 * t2 ^ 2/2) = (a1 * t1 ^ 2/2) + (a1 * t1 * (a1 * t1 / a2) – a2 * (a1 * t1 / a2) ^ 2/2) = (a1 * t1 ^ 2/2) + (a1 ^ 2 * t1 ^ 2 / a2 – a1 ^ 2 * t1 ^ 2 / 2a2) = a1 * t1 ^ 2/2 + a1 ^ 2 * t1 ^ 2 / 2a2.

Variables: a1 – the first acceleration (a1 = 4 m / s2); t1 is the time of accelerated movement (t1 = 10 s); a2 – second acceleration (a2 = 2 m / s2).

Calculation: S = a1 * t1 ^ 2/2 + a1 ^ 2 * t1 ^ 2 / 2a2 = 4 * 10 ^ 2/2 + 4 ^ 2 * 10 ^ 2 / (2 * 2) = 600 m.

Answer: The body with equal alternating motion has covered a path of 600 m.



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