The body, brought out of the state of rest, moving uniformly accelerated, covered a path of 180 m

The body, brought out of the state of rest, moving uniformly accelerated, covered a path of 180 m in 15 s. what distance did the body travel in 5 s?

To find the distance traveled by the body under consideration in only 5 seconds of motion, we use the equality (we use the formula: S = a * t2 / 2, from where we express: a (constant acceleration) = 2S / t2): 2S1 / t12 = a = 2S ^ 2 / t2 ^ 2, whence we express: S2 = 2S1 * t2 ^ 2 / 2t1 ^ 2 = S1 * t2 ^ 2 / t12

Values of variables: S1 – full path of the body (S1 = 180 m); t2 – considered time (t2 = 5 s); t1 – total travel time (t1 = 15 s).

Let’s perform the calculation: S2 = S1 * t2 ^ 2 / t1 ^ 2 = 180 * 5 ^ 2/15 ^ 2 = 20 m.

Answer: In 5 seconds, the body should have covered a path of 20 meters.