The body came out of a state of rest and after 15 seconds the speed reached 45 m / s to determine

The body came out of a state of rest and after 15 seconds the speed reached 45 m / s to determine the path that the body will pass with the same acceleration in 35 seconds.

Given:

V0 = 0 m / s – initial velocity of the body;

V1 = 45 m / s – the speed of the body through the time interval t;

t = 15 s;

t1 = 35 seconds.

It is required to find the acceleration a (m / s ^ 2) and the path S (m) that the body will pass in time t1.

a = (V1 – V0) / t = (45 – 0) / 15 = 3 m / s ^ 2.

S = V0 * t1 + a * t1 ^ 2/2 = 0 * 35 + 3 * 35 * 35/2 = 3675/2 = 1837.2 meters.

Answer: the acceleration of the body is 3 m / s ^ 2, in 35 seconds the body will cover a path equal to 1837 meters.



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