# The body changed its speed from 5m / s to 60 km / h in 10s. determine the acceleration with which the body

August 30, 2021 | education

| **The body changed its speed from 5m / s to 60 km / h in 10s. determine the acceleration with which the body is moving and the distance traveled by the body in the first 6 seconds.**

V0 = 5 m / s.

V = 60 km / h = 16.7 m / s.

t1 = 10 s.

t2 = 6 s.

a -?

S2 -?

The acceleration of a body is a vector physical quantity that shows how quickly the velocity of the body changes: a = (V – V0) / t, where V, V0 are the final and initial velocity of the body, t is the time during which the velocity changes …

a = (16.7 m / s – 5 m / s) / 10 s = 1.17 m / s2.

The path S traversed by the body, with uniformly accelerated movement, is determined by the formula: S = V0 * t + a * t2 / 2.

S2 = 5 m / s * 6 s + 1.17 m / s2 * (6 s) 2/2 = 51 m.

Answer: a = 1.17 m / s2, S2 = 51 m.

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