The body falls freely down. How long will it fly by in the sixth second of its fall?

To find the path that a given body should fly in the sixth second of its free fall, we apply the formula: h (6) = h6 – h5 = g * t6 ^ 2/2 – g * t5 ^ 2/2 = g * (t6 ^ 2 – t5 ^ 2) / 2.

Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); t6 – first time (t6 = 6 s); t5 – second time (t5 = 5 s).

Calculation: h (6) = g * (t6 ^ 2 – t5 ^ 2) / 2 = 10 * (6 ^ 2 – 5 ^ 2) / 2 = 55 m.

Answer: In the sixth second of the fall, a given body will fly 55 meters.