The body falls freely from a height of 10m. Determine the speed at a height of 5m.

h1 = 10 m.
h2 = 5 m.
g = 9.8 m / s ^ 2.
V0 = 0 m / s.
V -?
When the body falls from the height h1 to the height h2, the body passes the path S = h1 – h2.
A freely falling body moves with an acceleration of gravity g; the formulas for uniformly accelerated motion are valid for it.
S = (V ^ 2 – V0 ^ 2) / 2 * g.
Since V0 = 0 m / s, the formula will take the form S = V ^ 2/2 * g.
V = √ (2 * g * S).
V = √ (2 * 9.8 m / s ^ 2 * (10m – 5m)) = 9.8 m / s.
Answer: the speed of the body at a height of 5 m will be V = 9.8 m / s.