The body falls freely from a height of 125 m. How long will it fall? What will be his speed

The body falls freely from a height of 125 m. How long will it fall? What will be his speed at the end of this path? Disregard air resistance.

1) S = V0 * t + a * t² / 2, where S is the fall height (S = 125 m), V0 is the initial velocity (the body fell freely, V0 = 0 m / s), t is the fall time (t = 125 m), a is the acceleration of the body (a = g, g is the acceleration of gravity (g = 10 m / s²)).

S = g * t² / 2.

t = sqrt (2S / g) = sqrt (2 * 125/10) = sqrt (25) = 5 s.

2) S = (V² – V0²) / 2a.

S = V² / 2g.

V = sqrt (2g * S) = sqrt (2 * 10 * 125) = sqrt (2500) = 50 m / s.

Answer: The body fell for 5 s and had a speed of 50 m / s at the time of landing.