The body falls freely from a height of 12m. At what height from the surface of the Earth will its kinetic

The body falls freely from a height of 12m. At what height from the surface of the Earth will its kinetic energy be five times its potential energy?

Initial data: h0 (initial body height) = 12 m; Ek1 (kinetic energy at the desired altitude) = 5Ep1 (potential energy).

To find the height at which the falling body will need to be, we use the equality: Ep0 = Ek1 + Ep1 = 5Ep1 + Ep1 = 6Ep1 and m * g * h0 = 6 * m * g * h1, whence h1 = h0 / 6.

Calculation: h1 = h0 / 6 = 12/6 = 2 m.

Answer: D) the falling body must be at a height of 2 m.



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