The body falls freely from a height of 180m. Divide this distance into such sections that the body passes

The body falls freely from a height of 180m. Divide this distance into such sections that the body passes them at equal intervals of time.

We use the equation of body motion for uniformly accelerated motion:
s (t) = v0 * t + a * t² / 2, since our initial speed v0 is equal to zero, then:
s (t) = 9.81 * t² / 2.
Substitute t equal to 1 second, 2 seconds into the equation and determine the distance s.
s (1) = 9.81 * 1² / 1 = 4.905 meters.
s (2) = 9.81 * 2² / 1 = 19.62 meters.
s (3) = 9.81 * 3² / 1 = 44.145 meters.
s (4) = 9.81 * 4² / 1 = 78.48 meters.
s (5) = 9.81 * 5² / 1 = 122.625 meters.
s (6) = 9.81 * 6² / 1 = 176.58 meters.
s (6.06) = 9.81 * 6² / 1 = 180 meters.