The body falls freely from a height of 46m. What is the speed of the body at the moment of falling to the surface of the earth?

Initial data: H (height from which the body fell) = 46 m; V0 (initial velocity of the body, free fall) = 0 m / s.

Constants: according to the condition of the problem, g (acceleration of gravity) = 9.8 m / s ^ 2 = a (acceleration with which the body fell).

The speed of the body at the moment of falling onto the earth’s surface is determined from the formula: H = (V ^ 2 – V0 ^ 2) / 2a = V ^ 2 / 2g, whence V = √ (2g * H).

Let’s calculate: V = √ (2 * 9.8 * 46) = √901.6 = 30 m / s.

Answer: At the moment of falling to the surface of the earth, the speed of the body will be 30 m / s.