# The body falls freely from a height of 60 m. At what height from the earth’s surface

The body falls freely from a height of 60 m. At what height from the earth’s surface, the kinetic and potential energies of the body will be the same?

This problem should be considered as a general phenomenon for the free fall of a body from any height.
At the beginning of the fall, the potential energy of the body is maximum E potential = mgh, while the kinetic energy is equal to zero (E kinet = mv² / 2 (the speed at the beginning of the fall is zero)).
At the end of the fall, on the contrary, E potential is equal to zero, E potential is at its maximum.
In this case, the total energy of the body remains unchanged – E total = E potential + E will throw, and it is always equal in its value to E total = E potential maximum at the beginning of the fall (or E will throw maximum at the end of the fall).
As the body falls, a mutual transfer of energies occurs (potential decreases, kinetic increases).
Obviously, their values ​​will equal half of the path covered by the body, regardless of the height from which the body begins to fall (at this moment E potential = (mgh) / 2). The potential energy will be reduced by exactly half.
Consequently, the kinetic exactly at this point will equal the potential, since in total they will represent the same constant value – E total = 0.5 E potential (from the maximum value) + 0.5 E will throw (from the maximum value).
Thus, at a height of 30 meters, the kinetic and potential energies of our body will be the same.
And – wider – for a free fall of a body from any height, its energies will be equal (E potential = E throw) exactly halfway (height) of the fall.

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