The body falls freely from a height of H = 60 m. Determine the height at which its kinetic

The body falls freely from a height of H = 60 m. Determine the height at which its kinetic energy is twice its potential.

H = 60 m.
g = 9.8 m / s ^ 2.
Ek1 = 2 * En1.
Н1 -?
The total energy of the body at the moment of movement consists only of the potential energy E = En.
En = m * g * H.
At the height H1, its kinetic energy Ek1 = 2 * En1, and the total energy will be equal to E = Ek1 + En1.
E = 2 * En1 + En1.
En1 = m * g * H1.
m * g * H = 2 * m * g * H1 + m * g * H1.
H = 2 * H1 + H1.
H = 3 * H1.
H1 = H / 3.
Н1 = 60 m / 3 = 20 m.
Answer: at an altitude of H1 = 20 meters, the kinetic energy will be twice its potential energy.