The body falls freely from a height of h0 = 25m without initial speed. At what height will it be in 1s?

The distance that the body will travel in time t is given by the formula:

S = V0 * t + a * t ^ 2/2, where according to the condition V0 (initial velocity of the body) = 0 m / s (free fall), t (specified fall time), a (body acceleration, equally slow motion) = – g = – 10 m / s ^ 2.

For the moment of time t = 1 s.

S = 0 – g * t ^ 2/2.

S = – 10 * 1 ^ 2/2 = -5 m.

Let’s calculate the final body height:

h1 = h0 – S, where h0 (initial body height) = 25 m.

h1 = 25 – 5 = 20 m.

Answer: In 1 second, the body will be at a height of 20 meters.