The body falls freely from rest from a height of 50m. At what height will the body be after 3 seconds of fall?

To find the height at which the body should be taken, we use the formula: Δh = h0 – h1 = h0 – g * t ^ 2/2.
Variables and constants: h0 – initial height (h0 = 50 m); g – acceleration due to gravity (g ≈ 10 m / s2); t is the considered duration of the fall (t = 3 s).
Calculation: Δh = h0 – g * t ^ 2/2 = 50 – 10 * 3 ^ 2/2 = 50 – 45 = 5 m.
Answer: After 3 s, the taken body will be at a height of 5 m.