The body falls freely without initial speed from a height of 125m. Is the path it has traveled in the last two seconds?

Initial data: h (considered height) = 125 m; t (time until the fall) = 3 s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Total duration of the fall: t1 = √ (2h / g) = √ (2 * 125/10) = 5 s.

2) The height that the body will overcome before the given moment of fall: h1 = g * (t1 – t) ^ 2/2 = 10 * (5 – 2) ^ 2/2 = 45 m.

3) Height 2 s before the fall: h2 = h – h1 = 125 – 45 = 80 m.

Answer: In the remaining 2 seconds of free fall, the body will fly 80 meters.