The body falls from a greater height from the Naichi state of rest, the ratio of its potential and kinetic energy

The body falls from a greater height from the Naichi state of rest, the ratio of its potential and kinetic energy at the highest point, in the middle and at the lowest point near the earth. Height H = (100-29) m, body weight 7 kg.

Given:

H = 129 meters – the height from which the body falls;

m = 7 kg – body weight;

g = 10 m / s ^ 2 – acceleration of gravity;

V0 = 0 m / s is the initial velocity of the body.

It is required to determine the potential Ep and kinetic Ek energy at the highest point, at the midpoint and at the surface of the earth.

Since the body falls without initial velocity, then at the maximum point the kinetic energy will be equal to zero, and the potential energy:

Ep max = m * g * H = 129 * 10 * 7 = 9030 N.

Further, the body will fall, its height will decrease, and its speed will increase. At half the height, its kinetic energy and potential will be equal (according to the law of conservation of energy):

Eк = Ep = m * g * H / 2 = 9030/2 = 4515 Newtons.

At the surface of the earth, all potential energy will be converted into kinetic energy:

Eк max = Ep max = 9030 N.

Answer: at the maximum height, the kinetic energy is zero, the potential energy is 9030 Newton, at the midpoint the kinetic and potential energy are equal to each other = 4515 Newton, at the surface of the earth the potential energy is zero, the kinetic energy is 9030 Newton.