The body falls from a height of 100 meters, what kinetic energy will the body have at the time of the fall

H = 100 meters – the height from which the body falls;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the kinetic energy of the body Eк (Joule) at the moment of falling.

Let m be the mass of this body. Then, at the height H, the body will have the following potential energy:

Ep = m * g * H.

In the process of a body falling, according to the law of conservation of energy, its potential energy will decrease, and its kinetic energy will increase. Immediately before hitting the ground, its potential energy will be zero, and its kinetic energy will be at its maximum. Then, according to the conservation law, the energy is:

Eк = Ep = m * g * H = 10 * 100 * m = 1000 * m (where m is body weight).

Answer: the kinetic energy of the body will be equal to 1000 * m Joules.