The body falls from a height of 2000 meters. How long will it take for it to pass the last 100 meters.

Initial data: h (full height of fall) = 2000 m; h1 (considered height) = 100 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Total fall time: h = g * t ^ 2/2, whence t = √ (2h / g) = √ (2 * 2000/10) = 20 s.

2) Initial height: h2 = h – h1 = 2000 – 100 = 1900 m.

3) Initial fall time: t2 = √ (2h2 / g) = √ (2 * 1900/10) = 19.49 s.

4) Time spent on the last 100 meters: t1 = t – t2 = 20 – 19.49 = 0.51 s.

Answer: The body will fly the last 100 m in 0.51 s.